x^2+5x=2450

Solution for x^2+5x=2450 equation:

x^2+5x=2450

We move all terms to the left:

x^2+5x-(2450)=0

a = 1; b = 5; c = -2450;
Δ = b2-4ac
Δ = 52-4·1·(-2450)
Δ = 9825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9825}=\sqrt{25*393}=\sqrt{25}*\sqrt{393}=5\sqrt{393}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{393}}{2*1}=\frac{-5-5\sqrt{393}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{393}}{2*1}=\frac{-5+5\sqrt{393}}{2}
$